5x+80=17x^2

Solution for 5x+80=17x^2 equation:

5x+80=17x^2

We move all terms to the left:

5x+80-(17x^2)=0

determiningTheFunctionDomain
-17x^2+5x+80=0

a = -17; b = 5; c = +80;
Δ = b2-4ac
Δ = 52-4·(-17)·80
Δ = 5465
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{5465}}{2*-17}=\frac{-5-\sqrt{5465}}{-34}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{5465}}{2*-17}=\frac{-5+\sqrt{5465}}{-34}
$